CvInvokeBitwiseAnd Method |
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Calculates per-element bit-wise logical conjunction of two arrays:
dst(I)=src1(I) & src2(I) if mask(I)!=0
In the case of floating-point arrays their bit representations are used for the operation. All the arrays must have the same type, except the mask, and the same size
Namespace:
Emgu.CV
Assembly:
Emgu.CV.World (in Emgu.CV.World.dll) Version: 4.1.1.3497 (4.1.1.3497)
Syntaxpublic static void BitwiseAnd(
IInputArray src1,
IInputArray src2,
IOutputArray dst,
IInputArray mask = null
)
Public Shared Sub BitwiseAnd (
src1 As IInputArray,
src2 As IInputArray,
dst As IOutputArray,
Optional mask As IInputArray = Nothing
)
public:
static void BitwiseAnd(
IInputArray^ src1,
IInputArray^ src2,
IOutputArray^ dst,
IInputArray^ mask = nullptr
)
static member BitwiseAnd :
src1 : IInputArray *
src2 : IInputArray *
dst : IOutputArray *
?mask : IInputArray
(* Defaults:
let _mask = defaultArg mask null
*)
-> unit
Parameters
- src1
- Type: Emgu.CVIInputArray
The first source array - src2
- Type: Emgu.CVIInputArray
The second source array - dst
- Type: Emgu.CVIOutputArray
The destination array - mask (Optional)
- Type: Emgu.CVIInputArray
Operation mask, 8-bit single channel array; specifies elements of destination array to be changed
See Also