CudaInvokeMultiply Method |
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Computes element-wise product of the two GpuMat: c = scale * a * b.
Namespace:
Emgu.CV.Cuda
Assembly:
Emgu.CV.World (in Emgu.CV.World.dll) Version: 4.0.1.3373 (4.0.1.3373)
Syntaxpublic static void Multiply(
IInputArray a,
IInputArray b,
IOutputArray c,
double scale = 1,
DepthType depthType = DepthType.Default,
Stream stream = null
)
Public Shared Sub Multiply (
a As IInputArray,
b As IInputArray,
c As IOutputArray,
Optional scale As Double = 1,
Optional depthType As DepthType = DepthType.Default,
Optional stream As Stream = Nothing
)
public:
static void Multiply(
IInputArray^ a,
IInputArray^ b,
IOutputArray^ c,
double scale = 1,
DepthType depthType = DepthType::Default,
Stream^ stream = nullptr
)
static member Multiply :
a : IInputArray *
b : IInputArray *
c : IOutputArray *
?scale : float *
?depthType : DepthType *
?stream : Stream
(* Defaults:
let _scale = defaultArg scale 1
let _depthType = defaultArg depthType DepthType.Default
let _stream = defaultArg stream null
*)
-> unit
Parameters
- a
- Type: Emgu.CVIInputArray
The first GpuMat to be element-wise multiplied. - b
- Type: Emgu.CVIInputArray
The second GpuMat to be element-wise multiplied. - c
- Type: Emgu.CVIOutputArray
The element-wise multiplication of the two GpuMat - scale (Optional)
- Type: SystemDouble
The scale - depthType (Optional)
- Type: Emgu.CV.CvEnumDepthType
Optional depth of the output array. - stream (Optional)
- Type: Emgu.CV.CudaStream
Use a Stream to call the function asynchronously (non-blocking) or null to call the function synchronously (blocking).
See Also