CudaInvokeHistEven Method |
http://www.emgu.com
Calculates histogram with evenly distributed bins for single channel source.
Namespace: Emgu.CV.CudaAssembly: Emgu.CV.Cuda (in Emgu.CV.Cuda.dll) Version: 3.0.0.2161 (3.0.0.2161)
Syntaxpublic static void HistEven(
IInputArray src,
IOutputArray hist,
int histSize,
int lowerLevel,
int upperLevel,
Stream stream = null
)
Public Shared Sub HistEven (
src As IInputArray,
hist As IOutputArray,
histSize As Integer,
lowerLevel As Integer,
upperLevel As Integer,
Optional stream As Stream = Nothing
)
public:
static void HistEven(
IInputArray^ src,
IOutputArray^ hist,
int histSize,
int lowerLevel,
int upperLevel,
Stream^ stream = nullptr
)
static member HistEven :
src : IInputArray *
hist : IOutputArray *
histSize : int *
lowerLevel : int *
upperLevel : int *
?stream : Stream
(* Defaults:
let _stream = defaultArg stream null
*)
-> unit
Parameters
- src
- Type: Emgu.CVIInputArray
The source GpuMat. Supports CV_8UC1, CV_16UC1 and CV_16SC1 types. - hist
- Type: Emgu.CVIOutputArray
Histogram with evenly distributed bins. A GpuMat<int> type. - histSize
- Type: SystemInt32
The size of histogram (number of levels) - lowerLevel
- Type: SystemInt32
The lower level - upperLevel
- Type: SystemInt32
The upper level - stream (Optional)
- Type: Emgu.CV.CudaStream
Use a Stream to call the function asynchronously (non-blocking) or null to call the function synchronously (blocking).
Return Value
Type:
Histogram with evenly distributed bins
See Also